Cell Cycle Review
Interphase- Stage at which the DNA(genetic material) is doubled
Check Points - G1 and G2. The integrity of the DNA is checked here.
Mitosis - Somatic Cell Division
2N-4N-2N
There is 1 cell division compared to 2 in Meiosis.
What is mitosis?
Interphase & mitosis
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Meiosis - Reduction Division
Packaging up half the genetic material into either sperm or eggs
There are 2 divisions compared to 1 in Mitosis
2N-4N-2N-N
Only one oocyte gets all the nutrients, therefore the others become polar bodies and die
Note: Homologous chromosomes pair up at Metaphase
Relating all this to Mendelian Genetics
When you are looking at more than one trait.
Example
T = tall
t = small
R = round
r = wrinkled
When the chromosomes line up one combination can be
T R
XXXXXXX OOOOOOO
xxxxxxxxxxx oooooooooo
t r
Duplication at Interphase of Meiosis then line up at Metaphase
T R
XXXXXXX
OOOOOOO
XXXXXXX
OOOOOOO
T R SEPARATION OF THE TRAITS
t r
xxxxxxxxxxx
oooooooooo
xxxxxxxxxxx
oooooooooo
t r
Result in gametes is:
T and R
t and r
after 1 cell division
Note: There is no Tr and rR combination
There will be if the chromosomes line up at Metaphase like this:
T r
XXXXXXX
oooooooooo
XXXXXXX
oooooooooo
xxxxxxxxxx
OOOOOOO
xxxxxxxxxx
OOOOOOO
t R
Result in gametes is:
T and r
t and R
Calculation phenotypic and genotypic ratios for a dihybrid cross
So what we have is a dihybrid cross
(Two traits are involved)
Using height and shape as above
T = tall
t = short
R= round
r= wrinkled
TtRr x TtRr
Gametes that can be passed on are:
T and R
t and r
Because of Independent assortment other possibilities are:
T and r
t and R
The possible gametes for both parents will be the same since they are both heterozygotes for both traits
Using Punnet Square
TR Tr tR tr
TR
Tr
rR
tr
Branching Method
Or 3:1 x 3:1
3 1
3 9 3
1 3 1
Will produce a 9:3:3:1 phenotypic ratio
9 tall and round
3 tall and wrinkled
3 small and round
1 small and wrinkled
From this we can see the genotypic ratio that is being formed.
Another way to figure the genotypic ratio for a dihybrid cross is to think of it as a monohybrid x monohybrid
If genotypic ratio for a monohybrid cross is 1:2:1, a dihybrid cross would be 1:2:1 x 1:2:1
so:
1AA 1DD 1AADD
2Dd 2AADd
1dd 1AAdd
2Aa 1DD 2AaDD
2Dd 4AaDd
1dd 2Aadd
1aa 1DD 1aaDD
2Dd 2aaDd
1dd 1aadd
Giving a genotypic ratio of?
Q. What is the probability of one of the F1 being double recessive?