How to Solve Problems Involving Pedigrees
- Since the pedigrees presented are simple pedigrees, the following
assumptions can be made:
- No new mutations occur in the families. This means that a dominant
trait must occur in a parent if it appears in a child. This also means
that if a recessive trait appears in a child but does not occur in
either parent, both parents must be heterozygous carriers for the trait.
- All traits are 100% penetrant. This means that if the genotype for
the trait occurs in an individual, the trail will appear.
- If neither parent is affected,
- the trait cannot be dominant.
- the trait could be recessive and either parent or both could be
heterozygous carriers.
- If one parent is affected,
- the trait could be dominant and the affected parent could be
heterozygous while the unaffected parent is not a carrier
- the trait could be recessive and the affected parent is homozygous
while the unaffected parent could be a heterozygous carrier
- If both parents are affected
- the trait could be dominant and both parents could be heterozygous
carriers which means that some of the children could be unaffected
- the trait could be recessive meaning that both parents would have to
be homozygous and all the children would have to be affected
- Consideration of X-linked or Y-linked traits:
- X-linked recessive
- affected male children must have, at least, an heterozygous
mother
- an affected female will transmit the trait to all male
children
- X-linked dominant
- affected males transmit the trait to all daughters
- affected sons must have an affected mother
- Y-linkage
- male to male transmission only
- no affected females
- Mitochondria associated traits
- affected females transmit the trait to all children
- affected males do not transmit the trait to any children
Pedigree Test Page
Pedigree A
Pedigree B
Pedigree C
Pedigree D