Bio 328. Spring 2005
KEY
Test #3
Provide concise answers in the space provided after each question. If you need more space, continue on the backside of the page. The potential value of each answer is 4 points unless otherwise noted in the margin.
1. (a) In the Figure below, circle the histidine
kinase domain of ETR1.

(b) Describe an experiment and results that revealed
whether histidine kinase activity is required for ETR1 function.
Ans.:
Scientists found that a modified gene that coded for an ETR1 protein that had an
only slightly altered histidine kinase domain, but no histidine kinase activity,
could substitute for a wild-type gene and maintain full ethylene sensitivity.
(c) What is the functional relationship of ETR1 to
CTR1 and how does ethylene binding change this relationship, and thus change the
function of CTR1?
Ans.
: In the absence of bound ethylene ETR1 binds to CTR1 allowing CTR1 to inhibit
the activity of a positive regulator EIN2. When ethylene binds to ETR1, it
releases CTR1 and this de-represses EIN2.
2. (a) Define what is EIN3, compare its relative
level in wild-type plants in the presence and absence of ethylene, and indicate
by what mechanism ethylene changes the level of EIN3.
Ans.:
EIN3 is a transcription factor that induces the transcription of ethylene
responsive genes. Its level is higher in the presence than in the absence of
ethylene, because ethylene presence on its receptors results in the inactivation
of two F-box proteins, EBF1 and EBF2. In the absence of ethylene these proteins
would promote the ubiquitination and subsequent destruction of EIN3.
(b) What is the functional relationship of EIN3 to
ERF1?
Ans.: One of the genes turned on by
EIN3 is the gene encoding ERF1.
(c) ERF1 is both a positive regulator and a negative
regulator of ethylene action. Explain.
Ans.:
ERF1 induces the increased transcription of a number of genes needed for
ethylene effects on plant growth and development, so it is a positive regulator
of ethylene action. It also increases the transcription of the genes for EBF1
and EBF2, which negatively regulate EIN3, so in this respect it is also a
negative regulator of ethylene action.
3. (a) A wound in one part of a plant induces other
parts of the same plant that are unwounded to make protease inhibitors. What are
the 2 hormones that can carry the wound message from the wound site to other
parts of the plant and what are the 2 routes by which these hormones travel?
Ans.:
The two hormones are systemin, which travels through the vascular system of
plants, and methyl jasmonate, which is a volatile hormone that travels through
the air.
(b) Knocking out the lipoxygenase gene would block
one of the two communication routes noted in your answer to 3(a). Explain why.
Ans.:
Lipoxygenase is needed to convert linolenic acid to Jasmonic acid, so knocking
out the gene that encodes this enzyme would block the formation of methyl
jasmonate and the air route of communication.
(c) Plants transformed with the antisense to a gene
that encodes an 18 amino acid peptide hormone look like wild-type plants. What
treatment would reveal how they are different from wild-type plants? Explain
your answer.
Ans.:
Allowing Manduca larvae to feed on wild-type and antisense plants would reveal
that these larvae do not grow as much on wild-type plants as they do on mutant
plants.
4. (a) ) Scientists have wondered what signals are
released at a wound site that induce the transduction events leading to the
production of protease inhibitors. Describe
evidence that suggests ATP could be one of those signals.
Ans.:
Concentrations of ATP that are released from wounded cells and accumulate at
wound sites are sufficient to induce superoxide production, and superoxide
production is an important prerequisite for systemin induction at the wound
site. Systemin can induce protease inhibitors in wounded plants.
(b) Animals have known P2 receptors that respond to
ATP. What is the evidence that plants may have receptors that are structurally
and functionally similar to the animal receptors?
Ans.:
Inhibitors that block the animal P2 receptors block ATP effects on plants and
ATP induces an increase in [Ca2+]cyt in plant cells like
it does in animal cells.
(c) Does ATP have to be hydrolyzed to serve its
signaling role? Give evidence for your answer.
Ans.: No, because non-hydrolyzable
forms of ATP can induce the same responses as normal ATP.
5. (a) What is the hypersensitive response of plants
to pathogens, and what is the survival benefit of this response for the plant?
Ans.:
The hypersensitive response is the induction of programmed cell death in cells
in and near the site of pathogen infection. This isolates the pathogen in dead
cells, inhibiting its movement to surrounding cells and thus limiting the
infection damage.
(b) What are three lines of evidence that salicylic
acid may help mediate the hypersensitive response in plants?
Ans.:
1) salicylic acid levels increase at the site of infection; 2) plants expressing
a bacterial enzyme that reduces salicylic acid content in cells are more
susceptible to infection than wild-type plants; 3) treating susceptible plants
with salicylic acid increases their ability to develop the hypersensitive
response.
(c) What is systemic acquired resistance, and what
changes occur in those parts of the plant that have acquired this resistance
that help to explain why they have become more resistant?
Ans.:
Systemic acquired resistance is a state of pathogen resistance in plants in
which the original attack of a pathogen confers increased resistance to
subsequent attack by pathogens in leaves and other parts of the plant that were
not infected by the original attack. A key change in parts of the plants that
have acquired resistance is that they are expressing pathogen resistance (PR)
proteins.
5
pts. 6. (a) The binding
of GTP activates G-proteins. What enzyme activity inactivates G-proteins, and
what subunit has this activity?
Ans.:
The GTPase activity of the a
subunit of G-proteins is the activity that inactivates G-proteins.
5
pts. (b) In the Figure
below, what protein serves the role of “relay” molecule, what is an example
of an Effector target of the relay molecule, and how does the activation of that
effector help further amplify the signal?
Ans.:
The relay molecule is the
a subunit of G-proteins; an effector target is phosphlipase C, which
generates from a PIP2 substrate IP3 and DAG, two agents that can amplify signals
further.
Bio 328- Test #3, continued, page 3
NAME:
5
pts. 7.
(a) If you knocked out a gene
encoding a Ga
protein in Arabidopsis, what is one response system you would disable in the
mutated plant?
Ans.:
ABA-induced stomal closure.
5
pts. (b) In the response
system you noted in your answer to 7 (a), describe the signal transduction
pathway starting with the inducer of the pathway through to the final response
induced.
Ans.:
In guard cells, ABA activates G protein, which induces increased [Ca2+]cyt,which
activates CDPK, which phosphorylates an inward K+ channel, which causes it to
close. In the absence of K+ uptake the cell cannot take up water and swell, and
the stomates cannot open.
8. (a)
What function of calmodulin helps account for its name?
Ans.:
Calmodulin modulates the [Ca2+]cyt by activating calcium
pumps that remove calcium from the cytosol by pumping it out of the cell or into
vacuoles or ER.
(b) What enzyme in a proposed wound signaling pathway
is activated by calmodulin, and what is the key signaling product of that
enzyme.
Ans.:
Calcium-activated calmodulin activates NADPH oxidase, and the main product is
superoxide, which can induce downstream wound signaling events.
(c) Calmodulin is small enough to diffuse into the
nucleus. What critical function is it known to play there?
Ans.: Nuclear calmodulin can bind
to and activate transcription factors.
9. (a) There are hundreds of G-protein receptors in
animals that initiate hundreds of different signal transduction chains leading
to different responses. What is one way animals, but not Arabidopsis plants, can
achieve specificity in the signaling response using the same kind of G-protein
intermediate step?
Ans.:
Some animals have 23 different Gα, six Gβ, and 12 Gγ subunits, and so have the potential to assemble more than a thousand
different G
proteins.
(b) Why does it appear that Arabidopsis plants cannot
use the same strategy as animals in achieving specificity of response through
G-protein intermediates?
Ans.: In
contrast to animals, plants have only one clearly identifiable Gα, one Gβ, and possibly two Gγ
proteins, and so they cannot achieve much diversity of their G-proteins by
different combinations of the alpha, beta, and gamma subunits.
(c) Increases in [Ca2+]cyt can
promote both the opening and closing of stomata. How do guard cells figure out
whether to swell or shrink when they experience an increase in [Ca2+]cyt?
Ans.:
Guard cells can distinguish different calcium oscillation frequencies.
Environmental signals that induce stomate closure have an oscillation period
separating them of more than 5 min.; signals that induce stomate opening have a
period of less than 5 min. Thus a calcium oscillation frequency of greater than
12/hr induces stomate opening, but a calcium-pulse frequency of less than 12/hr
induces stomate closure.